Cross-Domain AJAX calls using PHP
(1 votes, average: 5 out of 5)AJAX has become the core component of many web applications around us. And its fairly easy to handle AJAX now a days, with the help of various javascript libraries (ex: jQuery, Prototype, Mootools, YUI, etc). But there is one security issue that web browsers impose in doing AJAX calls - they don’t let you do AJAX calls in web servers different than yours. That means, if your script is in www.mydomain.com and you’re trying to do AJAX call to www.anotherdomain.com/get.php, then the browser will through error like: “Error: uncaught exception: Permission denied to call method XMLHttpRequest.open”.
Now, there are a number of solutions to this problem. Instead of explaining them all to you, lemme provide you the simplest one: using a PHP transport file. If you already know the thing and just need the script, download from here.
Others, let’s see an example implementation first.
Example use
1: xmlHttp.onreadystatechange=function()
2: {
3: if(xmlHttp.readyState==4)
4: {
5: alert(xmlHttp.responseText);
6: }
7: }
8:
9: xmlHttp.open(“GET”, ‘http://myserver.com/transport.php?action=’ +
10: urlencode(‘different-server.com/return_call.php’) +
11: ‘&method=get&data1=101&data2=pass’, true );
12:
13: xmlHttp.send(null);
Now, lets see how it works:
- The script makes an AJAX call to the myserver.com/transport.php with a few parameters:
- action = the target URL you need to fetch, from a different domain
- method = the HTTP method (post/get)
- data1, data2 = sample parameters for using as either query-string or POST fields
- When the request is received by transport.php, it uses cURL to make a call to the page mentioned in action.
- Based on the method, it either makes a GET request or a POST request. In both cases, it sends the extra parameters that are sent.
- After the response is received, transport.php echoes it. So, you have what you need!
Download
 |
transport.php Cross-Domain AJAX call transporter. Downloaded: 806 times |
Comments and suggestions are most welcomed 
10 Comments
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March 6th, 2008 at 4:26 am
Please please please add some caching mechanism to your script. You do not want to allow some kiddie to flood another website using your script. Even 1-minute cache is enough, but just don’t call this website everytime like this. Not only will it be slow but the other site owner might get angry at you.
March 6th, 2008 at 12:59 pm
Does it also support POST simulation?
Good Work Batman!
March 6th, 2008 at 1:05 pm
@H2: Of course. Thanks !
March 6th, 2008 at 1:05 pm
This is a nice tutorial with explanation. Well I want t o show if you want to use jquery (http://jquery.com/).
If you want to get json data , then you can easily use getJSON.
$.getJSON("http://api.flickr.com/services/feeds/photos_public.gne?tags=cat&tagmode=any&format=json&jsoncallback=?",function(data){
$.each(data.items, function(i,item){
$("").attr("src", item.media.m).appendTo("#images");
});
});
Or if you don’t want to get other type of data like XML or other type, then you have to use cURL in PHP:
$.ajax({type: "GET",
url : ”http://myserver.com/transport.php?action=’ +
urlencode(‘different-server.com/return_call.php’) +
‘&method=get&data1=101&data2=pass”,
success: function(serverResponse)
/*parse serverResponse data */
});
March 6th, 2008 at 5:22 pm
I think that Loic Hoguin’s recommendation is accurate.
No comment ?
March 6th, 2008 at 6:12 pm
@Loic Hoguin: I completely agree with you that this script shouldn’t allow other person from web to misuse it for their own use.
But I would suggest using $_SERVER[’REMOTE_ADDR’] to block request from scripts other than the server I’m invoking it from.
The reason I think that way is, in the project I used it, the other server was also mine and I needed to communicate between them. As the output was quite dynamic, caching couldn’t be done.
But then again, if needed, caching can be added easily. I will be uploading one with caching later tonight.
Thanks everybody for commenting !
March 6th, 2008 at 11:22 pm
Indeed, filtering using REMOTE_ADDR is the best if both servers are yours.
What’s important to note, too, is that if curl_exec can’t fetch the data for some reasons it will return false. That means that your script will echo nothing. People using it should take care on the javascript side to check the data they get and if it’s empty display an error.
March 7th, 2008 at 12:20 am
@Loic Hoguin: Yes, you’re right. Also, to be safe, using a http wraper class supporting both cURL and fsockopen (like mine one) can be suggested to avoid problem.
March 26th, 2008 at 10:47 pm
On the transport file you can’t get the action because is named url
You must change that line :
$action = $_REQUEST[’url’];
To :
$action = $_REQUEST[’action’];
Or change this :
xmlHttp.open(“GET”, ‘http://myserver.com/transport.php?action=’ + 10: urlencode(‘different-server.com/return_call.php’) + 11: ‘&method=get&data1=101&data2=pass’, true );
With this :
xmlHttp.open(“GET”, ‘http://myserver.com/transport.php?url=’ + 10: urlencode(‘different-server.com/return_call.php’) + 11: ‘&method=get&data1=101&data2=pass’, true );
April 7th, 2008 at 9:34 pm
there’s a typo:
you wrote this:
if ($key != ‘url’ || $key != ‘method’)
while you obviously meant this:
if ($key != ‘url’ && $key != ‘method’)
(since ($key != ‘url’ || $key != ‘method’) is always true)